(3x^2+5)(2x^5-1)=0

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Solution for (3x^2+5)(2x^5-1)=0 equation: 


Simplifying
(3x2 + 5)(2x5 + -1) = 0

Reorder the terms:
(5 + 3x2)(2x5 + -1) = 0

Reorder the terms:
(5 + 3x2)(-1 + 2x5) = 0

Multiply (5 + 3x2) * (-1 + 2x5)
(5(-1 + 2x5) + 3x2 * (-1 + 2x5)) = 0
((-1 * 5 + 2x5 * 5) + 3x2 * (-1 + 2x5)) = 0
((-5 + 10x5) + 3x2 * (-1 + 2x5)) = 0
(-5 + 10x5 + (-1 * 3x2 + 2x5 * 3x2)) = 0
(-5 + 10x5 + (-3x2 + 6x7)) = 0

Reorder the terms:
(-5 + -3x2 + 10x5 + 6x7) = 0
(-5 + -3x2 + 10x5 + 6x7) = 0

Solving
-5 + -3x2 + 10x5 + 6x7 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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